876. Middle of the Linked List
876. Middle of the Linked List
# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def middleNode(self, head: Optional[ListNode]) -> Optional[ListNode]:
        curr = head
        count = 1
        while curr.next != None:
            curr = curr.next
            count += 1
        
        res = head
        count = count // 2
        while count > 0:
            count -= 1
            res = res.next
        return res快慢指針
# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def middleNode(self, head: ListNode) -> ListNode:
        slow = head
        fast = head
        while fast and fast.next:
            slow = slow.next
            fast = fast.next.next
        return slow
