$ cat ./coding/1208-get-equal-substrings-within-budget.md

────────────────────────────────────────────────────────────

1208. Get Equal Substrings Within Budget

class Solution:
    def equalSubstring(self, s: str, t: str, maxCost: int) -> int:
        maxLen = 0
        currCost = 0
        start = 0

        for i in range(len(s)):
            currCost += abs(ord(s[i]) - ord(t[i]))

            while currCost > maxCost:
                currCost -= abs(ord(s[start]) - ord(t[start]))
                start += 1
            
            maxLen = max(maxLen, i - start + 1)
        
        return maxLen

$ ls ./coding/ | grep -v 1208-get-equal-substrings-within-budget